NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is


- AP0V0
- B2P0V0
- C
- Dzero
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Correct answer: D

$${W_{AEDA}} = + area\,of\,\Delta AED = + {1 \over 2}{P_0}{V_0}$$
$${W_{BCEB}} = - area\,of\Delta BCE = - {1 \over 2}{P_0}{V_0}$$
The net work done by the system is
$${W_{net}} = {W_{AEDA}} + {W_{BCEB}}$$
$$ = + {1 \over 2}{P_0}{V_0} - {1 \over 2}{P_0}{V_0} = 0$$
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