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Heat and Thermodynamics question

2013 · Q159
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Heat and Thermodynamics question

2013 · Q159

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua=10 J{U_a} = 10\,JUa​=10J. Along the path adc the amount of heat absorbed dQ1 === 50 J and the work obtained dW1 === 20 J whereas along the path abc the heat absorbed dQ2 = 36 J. The amount of work allong the path abc is

NEET 2013 (Karnataka) Physics - Heat and Thermodynamics Question 60 English
  1. A
    10 J
  2. B
    12 J
  3. C
    36 J
  4. D
    6 J
View written solutionFree

Correct answer: D

From first law of thermodynamics

Qadc=ΔUadc+Wadc{Q_{adc}} = \Delta {U_{adc}} + {W_{adc}}Qadc​=ΔUadc​+Wadc​

50 J=ΔUadc+20J50\,J = \Delta {U_{adc}} + 20J50J=ΔUadc​+20J

ΔUadc=30J\Delta {U_{adc}} = 30JΔUadc​=30J

Again

Qabc=ΔUabc+Wabc{Q_{abc}} = \Delta {U_{abc}} + {W_{abc}}Qabc​=ΔUabc​+Wabc​

Wabc=Qabc−ΔUabc{W_{abc}} = {Q_{abc}} - \Delta {U_{abc}}Wabc​=Qabc​−ΔUabc​

Wabc=36 J−30 J{W_{abc}} = 36\,J - 30\,JWabc​=36J−30J

Wabc=6 J{W_{abc}} = 6\,JWabc​=6J

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