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Heat and Thermodynamics question

2012 · Q97
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Heat and Thermodynamics question

2012 · Q97

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram.

AIPMT 2012 Mains Physics - Heat and Thermodynamics Question 55 English

If Q1, Q2, Q3 indicate the heat absorbed by the gas along the three processes and Δ\DeltaΔU1, Δ\DeltaΔU2, Δ\DeltaΔU3 indicate the change in internal energy along the three processes respectively, then
  1. A
    Q1 > Q2 > Q3 and Δ\DeltaΔU1 = Δ\DeltaΔU2 = Δ\DeltaΔU3
  2. B
    Q3 > Q2 > Q1 and Δ\DeltaΔU1 = Δ\DeltaΔU2 = Δ\DeltaΔU3
  3. C
    Q1 = Q2 = Q3 and Δ\DeltaΔU1 > Δ\DeltaΔU2 > Δ\DeltaΔU3
  4. D
    Q3 = Q2 = Q1 and Δ\DeltaΔU1 > Δ\DeltaΔU2 > Δ\DeltaΔU3
View written solutionFree

Correct answer: A

Initial and final condition is same for all process

ΔU1=ΔU2=ΔU3\Delta {U_1} = \Delta {U_2} = \Delta {U_3}ΔU1​=ΔU2​=ΔU3​

from first law of thermodynamics

ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta WΔQ=ΔU+ΔW

Work done

ΔW1>ΔW2>ΔW3\Delta {W_1} \gt \Delta {W_2} \gt \Delta {W_3}ΔW1​>ΔW2​>ΔW3​   (Area of P.V. graph)

So ΔQ1>ΔQ2>ΔQ3\Delta {Q_1} \gt \Delta {Q_2} \gt \Delta {Q_3}ΔQ1​>ΔQ2​>ΔQ3​

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