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Heat and Thermodynamics question

2005 · Q166
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Heat and Thermodynamics question

2005 · Q166

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
An ideal gas heat engine operates in Carnot cycle between 227oC and 127oC. It absorbs 6 ×\times× 104 cal of heat at higher temperature. Amount of heat converted to work is
  1. A
    4.8 ×\times× 104 cal
  2. B
    6 ×\times× 104 cal
  3. C
    2.4 ×\times× 104 cal
  4. D
    1.2 ×\times× 104 cal.
View written solutionFree

Correct answer: D

1−T2T1=1−Q2Q11 - {{{T_2}} \over {{T_1}}} = 1 - {{{Q_2}} \over {{Q_1}}}1−T1​T2​​=1−Q1​Q2​​

⇒1−400500=1−Q26×104 \Rightarrow 1 - {{400} \over {500}} = 1 - {{{Q_2}} \over {6 \times {{10}^4}}}⇒1−500400​=1−6×104Q2​​

⇒45=Q26×104⇒Q2=4.8×104cal \Rightarrow {4 \over 5} = {{{Q_2}} \over {6 \times {{10}^4}}} \Rightarrow {Q_2} = 4.8 \times {10^4}cal⇒54​=6×104Q2​​⇒Q2​=4.8×104cal

Net heat converted into work

=6.0×104−4.8×104=1.2×104cal = 6.0 \times {10^4} - 4.8 \times {10^4} = 1.2 \times {10^4}cal=6.0×104−4.8×104=1.2×104cal

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