NEETPhysicsElectrostaticsMCQ+4 / −1
A thin spherical shell is charged by some source. The potential difference between the two points and (in V) shown in the figure is:
(Take SI units)

- A
- B
- C
- DZero
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Correct answer: D
For uniformly charged spherical shell,
$$\begin{aligned} & V=\frac{k q}{R} \quad(\text { For } r \leq R) \\ & \therefore \quad V_C=V_P \\ & V_C-V_P=\text { Zero } \\ \end{aligned}$$
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