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Current Electricity question

2005 · Q141
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Current Electricity question

2005 · Q141

NEETPhysicsCurrent ElectricityMCQ+4 / −1
For the network shown in the figure the value of the current iii is

AIPMT 2005 Physics - Current Electricity Question 62 English
  1. A
    9V35{{9V} \over {35}}359V​
  2. B
    18V5{{18V} \over 5}518V​
  3. C
    5V9{{5V} \over 9}95V​
  4. D
    5V18{{5V} \over {18}}185V​
View written solutionFree

Correct answer: D

It is a balanced Wheatstone bridge. Hence resistance 4Ω\Omega Ω can be eliminated.

∴\therefore∴ Req=6×96+9=185{R_{eq}} = {{6 \times 9} \over {6 + 9}} = {{18} \over 5}Req​=6+96×9​=518​

∴i=VReq=5V18 \therefore i = {V \over {{R_{eq}}}} = {{5V} \over {18}}∴i=Req​V​=185V​

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