NEETPhysicsCenter of Mass and CollisionMCQ+4 / −1
A shell of mass 200 gm is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. The initial velocity of the shell is :
- A40 ms1
- B120 ms1
- C100 ms1
- D80 ms1
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Correct answer: C
As per laws of conservation of momentum
and energy, if v and V represents initial velocity of
shell of mass m and recoil velocity of gun of mass M
respectively, then
mv + MV = 0
Here (–) sign shows that recoil velocity of gun is
opposite to velocity of shell.
The energy of explosion is used to impart kinetic
energy to shell and gun so that we have
(mv2 + MV2) = 1.05 × 103
[0.2v2
- (4v2 / 400)] = 1.05 ×103
v2 = 104
v = 100 m/s
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