NEETPhysicsCenter of Mass and CollisionMCQ+4 / −1
A ball of mass 0.5 kg is dropped from a height of 40 m . The ball hits the ground and rises to a height of 10 m . The impulse imparted to the ball during its collision with the ground is (Take )
- A0
- B84 NS
- C21 NS
- D7 NS
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Correct answer: C

$$\begin{aligned} \& v_1=\sqrt{2 g h_1} \\ \& =\sqrt{2 \times 9.8 \times 40} \\ \& v_1=\sqrt{784}=28 \mathrm{~m} \mathrm{~s}^{-1} \\ \& \text { and } v_2=\sqrt{2 g h_2}=\sqrt{2 \times 9.8 \times 10} \\ \& =\sqrt{196}=14 \mathrm{~m} \mathrm{~s}^{-1} \\ \& \text { Impulse }=\Delta \vec{p}=m\left(\vec{v}_f-\vec{v}_i\right)=m\left(\vec{v}_2-\vec{v}_1\right) \\ \& =\frac{1}{2}(14-(-28)) \\ \& =21 \mathrm{NS} \end{aligned}$$
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