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Atoms and Nuclei question

2014 · Q136
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Atoms and Nuclei question

2014 · Q136

NEETPhysicsAtoms and NucleiMCQ+4 / −1
Hydrogen atom in ground state is excited by a monochromatic radiation of λ\lambdaλ = 975 A∘\mathop A\limits^ \circA∘​. Number of spectral lines in the resulting spectrum emitted will be
  1. A
    3
  2. B
    2
  3. C
    6
  4. D
    0 10
View written solutionFree

Correct answer: C

Energy of radiation :

E = 12375975{{12375} \over {975}}97512375​ = 12.7 eV

After absorbing a photon of energy 12.75 eV, the electron will reach to third excited state of energy –0.85 eV, since energy difference corresponding to n = 1 and n = 4 is 12.75 eV.

∴\therefore∴ Number of spectral lines emitted

= n(n−1)2=4(4−1)2{{n\left( {n - 1} \right)} \over 2} = {{4\left( {4 - 1} \right)} \over 2}2n(n−1)​=24(4−1)​ = 6

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