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Atoms and Nuclei question

2013 · Q139
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Atoms and Nuclei question

2013 · Q139

NEETPhysicsAtoms and NucleiMCQ+4 / −1
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)
  1. A
    6.675 MeV
  2. B
    13.35 MeV
  3. C
    2.67 MeV
  4. D
    26.7 MeV
View written solutionFree

Correct answer: A

Mass defect Δ\Delta Δm = 0.02866 a.m.u.

Energy = 0.02866 × 931 = 26.7 MeV

As 1H2 + 1H2 →\to→ 2He4

Energy liberated per a.m.u = 13.352{{13.35} \over 2}213.35​ MeV = 6.675 MeV

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