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Atoms and Nuclei question

2013 · Q140
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Atoms and Nuclei question

2013 · Q140

NEETPhysicsAtoms and NucleiMCQ+4 / −1
An electron in hydrogen atom makes a transition n1 →\to→ n2 where n1 and n2 are principal quantum numbers of the two states . Assuming Bohr's model to be valid, the time period of the electron in the initial state is eight times that in the final state. The possible values of n1 and n2 are
  1. A
    n1 = 6 and n2 = 2
  2. B
    n1 = 8 and n2 = 1
  3. C
    n1 = 8 and n2 = 2
  4. D
    n1 = 4 and n2 = 2
View written solutionFree

Correct answer: D

As T ∝\propto∝ n3

∴\therefore∴ T1T2=8T2T2{{{T_1}} \over {{T_2}}} = {{8{T_2}} \over {{T_2}}}T2​T1​​=T2​8T2​​ = (n1n2)3{\left( {{{{n_1}} \over {{n_2}}}} \right)^3}(n2​n1​​)3

Hence, n1 = 2n2

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