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Atoms and Nuclei question

2010 · Q156
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Atoms and Nuclei question

2010 · Q156

NEETPhysicsAtoms and NucleiMCQ+4 / −1
The mass of a 37Li{}_3^7Li37​Li Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of 37Li{}_3^7Li37​Li nucleus is nearly
  1. A
    46 MeV
  2. B
    5.6 MeV
  3. C
    3.9 MeV
  4. D
    23 MeV
View written solutionFree

Correct answer: B

For 37Li{}_3^7Li37​Li nucleus,

Mass defect, Δ\Delta ΔM = 0.042 u

∴\therefore∴ 1 u = 931.5 MeV/c2

∴\therefore∴ Δ\Delta ΔM = 0.042 × 931.5 MeV/c2 = 39.1 MeV/c2

Number of nucleons in 37Li{}_3^7Li37​Li is 7.

Binding energy per nucleon,

Ebn = 39.17{{39.1} \over 7}739.1​ = 5.6 MeV

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