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Atoms and Nuclei question

2008 · Q142
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Atoms and Nuclei question

2008 · Q142

NEETPhysicsAtoms and NucleiMCQ+4 / −1
The ground state energy of hydrogen atom is −-− 13.6 eV. When its electron is in the first excited state, its excitation energy is
  1. A
    10.2 eV
  2. B
    0
  3. C
    3.4 eV
  4. D
    6.8 eV
View written solutionFree

Correct answer: A

En = −13.6n2 - {{13.6} \over {{n^2}}}−n213.6​

E1 = -13.6 eV

E2 = −13.622 - {{13.6} \over {{2^2}}}−2213.6​ = -3.4 eV

∴\therefore∴ Δ\Delta ΔE = ( – 3.4) – ( – 13.6) = 10.2 eV.

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