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Atoms and Nuclei question

2006 · Q149
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Atoms and Nuclei question

2006 · Q149

NEETPhysicsAtoms and NucleiMCQ+4 / −1
The binding energy of deuteron is 2.2 MeV and that of 24{}_2^424​He is 28 MeV. If two deuterons are fused to form one 24{}_2^424​He then the energy released is
  1. A
    30.2 MeV
  2. B
    25.8 MeV
  3. C
    23.6 MeV
  4. D
    19.2 MeV
View written solutionFree

Correct answer: C

12H{}_1^2H12​H + 12H{}_1^2H12​H →\to→ 24He{}_2^4He24​He + energy

Energy released = 28 – 2 × 2.2 = 23.6 MeV

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