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Atoms and Nuclei question

2007 · Q127
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Atoms and Nuclei question

2007 · Q127

NEETPhysicsAtoms and NucleiMCQ+4 / −1
The total energy of electron in the ground state of hydrogen atom is −-− 13.6 eV. The kinetic energy of an electron in the first excited state is
  1. A
    6.8 eV
  2. B
    13.6 eV
  3. C
    1.7 eV
  4. D
    3.4 eV.
View written solutionFree

Correct answer: D

En = −13.6n2 - {{13.6} \over {{n^2}}}−n213.6​

E1 = -13.6 eV

E2 = −13.622 - {{13.6} \over {{2^2}}}−2213.6​ = -3.4 eV

Kinetic energy of an electron in the first excited state is

K = –E2 = 3.4 eV.

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