NEETPhysicsAtoms and NucleiMCQ+4 / −1
If M(A; Z), Mp and Mn denote the masses of the nucleus proton and neutron respectively in units of u (1 u = 931.5 MeV/c2) and BE represents its bonding energy in MeV, then
- AM(A, Z) = ZMp + (A Z)Mn BE
- BM(A, Z) = ZMp + (A Z)Mn + BE/c2
- CM(A, Z) = ZMp + (A Z)Mn BE/c2
- DM(A, Z) = ZMp + (A Z)Mn + BE
View written solutionFree
Correct answer: C
Mass defect = ZMp + (A –Z)Mn – M(A, Z)
= ZMp + (A –Z)Mn – M(A, Z)
M(A, Z) = ZMp + (A Z)Mn
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