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Atoms and Nuclei question

2003 · Q145
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Atoms and Nuclei question

2003 · Q145

NEETPhysicsAtoms and NucleiMCQ+4 / −1
An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The Coulomb force F→\overrightarrow FF between the two is
  1. A
    Ke2r2r^K{{{e^2}} \over {{r^2}}}\widehat rKr2e2​r
  2. B
    −Ke2r3r^- K{{{e^2}} \over {{r^3}}}\widehat r−Kr3e2​r
  3. C
    Ke2r3r^K{{{e^2}} \over {{r^3}}}\widehat rKr3e2​r
  4. D
    −Ke2r2r^- K{{{e^2}} \over {{r^2}}}\widehat r−Kr2e2​r
View written solutionFree

Correct answer: D

The charge on hydrogen nucleus q1 = +e

charge on electron, q2 = –e

Coulomb force, F = K(+e)(−e)r2K{{\left( { + e} \right)\left( { - e} \right)} \over {{r^2}}}Kr2(+e)(−e)​

= −Ke2r3r→- {{K{e^2}} \over {{r^3}}}\overrightarrow r−r3Ke2​r

= −Ke2r2r^ - {{K{e^2}} \over {{r^2}}}\widehat r−r2Ke2​r

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