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Atoms and Nuclei question

2003 · Q148
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Atoms and Nuclei question

2003 · Q148

NEETPhysicsAtoms and NucleiMCQ+4 / −1
The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of 24{}_2^424​ He is
(Given helium nucleus mass ≈\approx≈ 4.0015 u.)
  1. A
    0.0305 J
  2. B
    0.0305 erg
  3. C
    28.4 MeV
  4. D
    0.061 u
View written solutionFree

Correct answer: C

Mass defect(Δ\Delta Δm) = 2MP

  • 2MN – MHe

    ⇒\Rightarrow⇒ Δ\Delta Δm = 2 × 1.0074 + 2 × 1.0087 – 4.0015

    ⇒\Rightarrow⇒ Δ\Delta Δm = 0.0307

    Now as per relation, E = Δ\Delta Δm × 931 MeV

    = 0.0307 × 931 = 28.4 MeV
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