NEETPhysicsAtoms and NucleiMCQ+4 / −1
A deutron is bombarded on 8O16 nucleus then -particle is emitted. The product nucleus is
- A7N13
- B5B10
- C4Be9
- D7N14
View written solutionFree
Correct answer: D
8O16 + 1H2 7N14 + 2He4
So when a deuteron is bombarded on 8O16 nucleus
then an -particle (2He4) is emitted and the product
nucleus is 7N14.
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