NEETChemistryThermodynamicsMCQ+4 / −1
Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure
of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]
- A25 J
- B30 J
- C-30 J
- D5 kJ
View written solutionFree
Correct answer: C
W = –Pext (V2–V1)
Pext = 2 bar
V1 = 0.1 L
V2 = 0.25 L
W = –2 bar[0.25 – 0.1] L
W = –2 × 0.15 bar L
W = –0.30 bar L
W = (–0.30) × 100 = –30 J
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