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Thermodynamics question

2015 · Q97
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Thermodynamics question

2015 · Q97

NEETChemistryThermodynamicsMCQ+4 / −1
The heat of combination of carbon to CO2 is −-−393.5 kJ/mol. The heat released upon formation of 35.2 g of CO2 from carbon and oxygen gas is
  1. A
    + 315 kJ
  2. B
    −-−630 kJ
  3. C
    −-− 3.15 kJ
  4. D
    −-− 315 kJ
View written solutionFree

Correct answer: D

To determine the heat released when 35.2 g of CO2 is formed from carbon and oxygen gas, we will follow these steps:

1. Calculate the number of moles of CO2:

The molar mass of CO2 can be calculated as follows:

Carbon (C): 12.01 g/mol

Oxygen (O): 16.00 g/mol

So, the molar mass of CO2 is:

$$12.01 + (16.00 \times 2) = 12.01 + 32.00 = 44.01 \, \text{g/mol}$$

The number of moles of CO2 in 35.2 g is calculated using:

$$\text{Number of moles} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{35.2 \, \text{g}}{44.01 \, \text{g/mol}} \approx 0.8 \, \text{moles}$$

2. Calculate the heat released for 0.8 moles of CO2:

The heat of combination given is -393.5 kJ/mol. This is the energy released when 1 mole of CO2 is formed:

$$\text{Heat released} = \text{Number of moles} \times \text{Heat of combination}$$

$$\text{Heat released} = 0.8 \, \text{moles} \times -393.5 \, \text{kJ/mol} = -314.8 \, \text{kJ}$$

After rounding, the heat released is approximately -315 kJ.

Answer: Option D $-$ 315 kJ.

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