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Thermodynamics question

2009 · Q117
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Thermodynamics question

2009 · Q117

NEETChemistryThermodynamicsMCQ+4 / −1
From the following bond energies :
H −-− H bond energy   : 431.37 kJ mol−-−1
C === C bond energy   : 606.10 kJ mol−-−1
C −-− C bond energy   : 336.49 kJ mol−-−1
C −-− H bond energy   : 410.50 kJ mol−-−1
Enthalpy for the reaction,
AIPMT 2009 Chemistry - Thermodynamics Question 57 English
will be
  1. A
    −-− 243.6 kJ mol−-−1
  2. B
    −-− 120.0 kJ mol−-−1
  3. C
    553.0 kJ mol−-−1
  4. D
    1523.6 kJ mol−-−1
View written solutionFree

Correct answer: B

Δ\Delta ΔHreaction = Σ(Bond enthalpy)reactants

– Σ(Bond enthalpy)products

= [B.E(C-C) + B.E(H-H) + 4×\times×B.E(C-H)]

- [B.E(C-C) + 6×\times×B.E(C-H)]

= [606.10 + 4(410.50) + 431.37]

– [336.49 + 6(410.50)]

= 2679.47 – 2799.49

= – 120.02 kJ mol–1

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