NEETChemistryThermodynamicsMCQ+4 / −1
Consider the following reactions :
(i) H+(aq) + OH(aq) = H2O(l), H = X1 kJ mol1
(ii) H2(g) + 1/2O2(g) = H2O(l), H = X2 kJ mol1
(iii) CO2(g) + H2(g) = CO(g) + H2O(l), H = X3 kJ mol1
(iv) C2H2(g) + 5/2O2(g) = 2CO2(g) + H2O(l), H = +X4 kJ mol1
Enthalpy of formation of H2O(l) is
(i) H+(aq) + OH(aq) = H2O(l), H = X1 kJ mol1
(ii) H2(g) + 1/2O2(g) = H2O(l), H = X2 kJ mol1
(iii) CO2(g) + H2(g) = CO(g) + H2O(l), H = X3 kJ mol1
(iv) C2H2(g) + 5/2O2(g) = 2CO2(g) + H2O(l), H = +X4 kJ mol1
Enthalpy of formation of H2O(l) is
- A+X3 kJ mol1
- BX4 kJ mol1
- C+X1 kJ mol1
- DX2 kJ mol1
View written solutionFree
Correct answer: D
Chemical equation for the formation of H2O(l)
is
H2(g) + 1/2O2(g) = H2O(l)
Because enthalpy of formation of a compound is
the heat absorbed or released when one mole of this
substance is formed from its constituent elements.
Thus, enthalpy of formation of H2O is –X2 kJ mol–1
where negative sign shows that the reaction is
exothermic.
Equation (i) represents nutralisation reaction.
Equation (iii) represents hydrogenation reaction.
Equation (iv) represents combustion reaction.
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