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Thermodynamics question

2009 · Q116
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Thermodynamics question

2009 · Q116

NEETChemistryThermodynamicsMCQ+4 / −1
The values of Δ\DeltaΔH and Δ\DeltaΔS for the reaction,

C(graphite) + CO2(g) →\to→  2CO(g)

are 170 kJ and 170 J K−-−1, respectively. This reaction will be spontaneous at
  1. A
    910 K
  2. B
    1110 K
  3. C
    510 K
  4. D
    710 K
View written solutionFree

Correct answer: B

We know, Δ\Delta ΔG = Δ\Delta ΔH – TΔ\Delta ΔS

For reaction to be spontaneous, Δ\Delta ΔG < 0

⇒\Rightarrow⇒ Δ\Delta ΔH – TΔ\Delta ΔS < 0

⇒\Rightarrow⇒ 170 ×\times× 103 - T(170) < 0

⇒\Rightarrow⇒ T > 1000 K

Among the given temperatures, only 1110 K is greater than 1000 K thus, at this temperate the reaction will be spontaneous.

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