NEETChemistryRedox ReactionsMCQ+4 / −1
In acidic medium, H2O2 changes Cr2O72- to CrO5 which has two
(OO) bonds. Oxidation state of Cr in CrO5 is
(OO) bonds. Oxidation state of Cr in CrO5 is
- A+5
- B+3
- C+6
- D10
View written solutionFree
Correct answer: C
CrO5
has butterfly structure having two
peroxo bonds.

Peroxo oxygen has –1 oxidation state.
Let oxidation state of Cr be ‘x’
CrO5 : x + 4(–1) + 1 (–2) = 0
x = +6
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