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Redox Reactions question

2008 · Q89
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Redox Reactions question

2008 · Q89

NEETChemistryRedox ReactionsMCQ+4 / −1
Number of moles of MnO4−_4^{ - }4−​ required to oxidize one mole of ferrous oxalate completely in acidic medium will be
  1. A
    7.5 moles
  2. B
    0.2 moles
  3. C
    0.6 moles
  4. D
    0.4 moles
View written solutionFree

Correct answer: C

The balanced ionic equation for oxidation of ferrous oxalate by MnO4– in acidic medium is as follows :

3MnO4- + 5FeC2O4 + 24H+ →\to→


3Mn2+ + 10CO2

  • 12H2O + 5Fe3+

    Thus, 5 moles of FeC2O4 require 3 moles of MnO4-.

    So, 1 mole of FeC2O4 requires

    = 35{3 \over 5}53​ = 0.6 moles of MnO4-
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