NEETChemistryRedox ReactionsMCQ+4 / −1
Oxidation numbers of P in PO, of S in SO and that of Cr in Cr2O are respectively
- A+3, +6 and +5
- B+5, +3 and +6
- C3, +6 and + 6
- D+5, +6 and +6
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Correct answer: D
Let oxidation number of P in PO4
3– be x.
x + 4(–2) = –3
x = +5
Let oxidation number of S in SO4
2– be y.
y + 4(–2) = –2
y = +6
Let oxidation number of Cr in Cr2O7
2– be z.
2z + 7(–2) = –2
z = +6
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