$$\mathrm{F}^{-1}, \mathrm{~N}^{-3}, \mathrm{Na}^{+} ~\& ~\mathrm{O}^{-2}$$

all ions are isoelectronic containing $10 e^{-}$

$$\mathrm{Z}_{\text {eff }} \rightarrow \mathrm{Na}^{+}>\mathrm{F}^{-}>\mathrm{O}^{-2}>\mathrm{N}^{-3}$$

order of radius $$\rightarrow \mathrm{N}^{-3}>\mathrm{O}^{-2}>\mathrm{F}^{-}>\mathrm{Na}^{+}$$

$\rightarrow$ Nitrogen to achieve Noble gas configuration it gain $3 e^{-}$, & form $\mathrm{N}^{-3}$