NEETChemistryP Block ElementsMCQ+4 / −1
Match List I with List II:
| List I |
List II |
||
|---|---|---|---|
| (A) | Coke | (I) | Carbon atoms are sp hybridised |
| (B) | Diamond | (II) | Used as a dry lubricant |
| (C) | Fullerene | (III) | Used as a reducing agent |
| (D) | Graphite | (IV) | Cage like molecules |
Choose the correct answer from the options given below:
- AA-IV, B-I, C-II, D-III
- BA-III, B-I, C-IV, D-II
- CA-III, B-IV, C-I, D-II
- DA-II, B-IV, C-I, D-III
View written solutionFree
Correct answer: B
Coke : It is used as reducing agent in carbon reduction methods. (in metallurgical process)
Diamond : It is a allotrope of carbon in which each carbon is $\mathrm{sp}^{3}$ hybridised.

Fullerene : It contains pentagonal & hexagonal rings (cage like structure)
Graphite : It is soft solid because graphite layers are bonded with weak Vander Wall attractions.
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