NEETChemistryP Block ElementsMCQ+4 / −1
Na2B4O7 X + NaBO2
in the above reaction the product "X" is :
- ANaB3O5
- BH3BO3
- CB2O3
- DNa2B2O5
View written solutionFree
Correct answer: C
Na2B4O7 $\xrightarrow{\Delta} $ B2O3 + 2NaBO2
Product X is B2O3
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