NEETChemistryIonic EquilibrumMCQ+4 / −1
What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed?
- A2.0
- B7.0
- C1.04
- D12.65
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Correct answer: D
HCl + NaOH NaCl + H2O
Initial 0.01 0.1 0 0
Final 0 0.09 0.01 0.01
As equal volumes of HCl and NaOH are added so
the volume of resulting solution becomes double
and the concentration of the solution becomes half.
[OH-] = = 0.045 M
pOH = – log[OH–
] = –log [0.045] = 1.35
pH = 14 – pOH = 14 – 1.35 = 12.65
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