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Ionic Equilibrum question

2013 · Q102
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Ionic Equilibrum question

2013 · Q102

NEETChemistryIonic EquilibrumMCQ+4 / −1
Accumulation of lactic acid (HC3H5O3), a monobasic acid in tissues leads to pain and a feeling of fatigue. In a 0.10 M aqueous solution, lactic acid is 3.7% dissociates. The value of dissociation constant, Ka, for this acid will be
  1. A
    1.4 ×\times× 10−-−5
  2. B
    1.4 ×\times× 10−-−4
  3. C
    3.7 ×\times× 10−-−4
  4. D
    2.8 ×\times× 10−-−4
View written solutionFree

Correct answer: B

α=Kac\alpha = \sqrt {{{{K_a}} \over c}} α=cKa​​​

⇒\Rightarrow⇒ 0.037 = Ka0.10\sqrt {{{{K_a}} \over {0.10}}} 0.10Ka​​​

⇒\Rightarrow⇒ Ka = (0.037)2 ×\times× 0.10

= 1.37 ×10–4

≃\simeq≃ 1.4 ×\times× 10−-−4

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