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Ionic Equilibrum question

2013 · Q101
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Ionic Equilibrum question

2013 · Q101

NEETChemistryIonic EquilibrumMCQ+4 / −1
KMnO4 can be prepared from K2MnO4 as per the reaction,

3MnO42−-− + 2H2O ⇌\rightleftharpoons⇌ 2MnO4−-− + MnO2 + 4OH−-−

The reaction can go to completion by removing OH−-− ions by adding
  1. A
    CO2
  2. B
    SO2
  3. C
    HCl
  4. D
    KOH
View written solutionFree

Correct answer: A

KOH is the base thus, it gives OH– ions thus it cannot remove OH– ions from reaction mixture but it adds on the concentration of OH– ions.

So, an acid must be added but if a strong acid is added to the reaction mixture then in acidic condition the MnO4 – formed reduces to give Mn2+ thus, HCl which is a strong acid and SO2 which on treating with water forms a strong H2SO4 cannot be used for this purpose.

Thus, CO2 which forms H2CO3 a weak acid reacts to remove OH– but not that much acidic that MnO4 – undergo reduction. Thus, CO2 is used for this reaction for completion.

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