NEETChemistryIonic EquilibrumMCQ+4 / −1
KMnO4 can be prepared from K2MnO4 as per the reaction,
3MnO42 + 2H2O 2MnO4 + MnO2 + 4OH
The reaction can go to completion by removing OH ions by adding
3MnO42 + 2H2O 2MnO4 + MnO2 + 4OH
The reaction can go to completion by removing OH ions by adding
- ACO2
- BSO2
- CHCl
- DKOH
View written solutionFree
Correct answer: A
KOH is the base thus, it gives OH–
ions thus
it cannot remove OH–
ions from reaction mixture
but it adds on the concentration of OH–
ions.
So,
an acid must be added but if a strong acid is added
to the reaction mixture then in acidic condition the
MnO4
–
formed reduces to give Mn2+ thus, HCl
which is a strong acid and SO2 which on treating
with water forms a strong H2SO4 cannot be used
for this purpose.
Thus, CO2 which forms H2CO3 a
weak acid reacts to remove OH–
but not that much
acidic that MnO4
–
undergo reduction. Thus, CO2 is
used for this reaction for completion.
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