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Ionic Equilibrum question

2004 · Q109
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Ionic Equilibrum question

2004 · Q109

NEETChemistryIonic EquilibrumMCQ+4 / −1
The solubility product of a sparingly soluble salt AX2 is 3.2 ×\times× 10−-−11. Its solubility (in moles/L) is
  1. A
    5.6 ×\times× 10−-−6
  2. B
    3.1 ×\times× 10−-−4
  3. C
    2 ×\times× 10−-−4
  4. D
    4 ×\times× 10−-−4
View written solutionFree

Correct answer: C

AX2⇌A2++2X-
ss2s


Ksp = = [A2+] [X– ]2 = s × (2s)2 = 4s3

$ \Rightarrow $ 3.2 $ \times $ 10$-$11 = 4s3

$ \Rightarrow $ s3 = 8 × 10–12

$ \Rightarrow $ s = 2 × 10–4 mol L–1
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