NEETChemistryIonic EquilibrumMCQ+4 / −1
The solubility product of a sparingly soluble salt AX2 is 3.2 1011. Its solubility (in moles/L) is
- A5.6 106
- B3.1 104
- C2 104
- D4 104
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Correct answer: C
Ksp = = [A2+] [X– ]2 = s × (2s)2 = 4s3
$ \Rightarrow $ 3.2 $ \times $ 10$-$11 = 4s3
$ \Rightarrow $ s3 = 8 × 10–12
$ \Rightarrow $ s = 2 × 10–4 mol L–1
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