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Electrochemistry question

2022 · Q131
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Electrochemistry question

2022 · Q131

NEETChemistryElectrochemistryMCQ+4 / −1

Standard electrode potential for the cell with cell reaction

Zn(s) + Cu2+(aq) →\to→ Zn2+(aq) + Cu(s)

is 1.1 V. Calculate the standard Gibbs energy change for the cell reaction. (Given F = 96487 C mol−-−1)

  1. A
    −-−200.27 J mol−-−1
  2. B
    −-−200.27 kJ mol−-−1
  3. C
    −-−212.27 kJ mol−-−1
  4. D
    −-−212.27 J mol−-−1
View written solutionFree

Correct answer: C

Zn(s) + Cu2+(aq) $\to$ Zn2+(aq) + Cu(s)

E$_{cell}^0$ = 1.1 V

$\Delta$G$^\circ$ = $-$nFE$_{cell}^0$

$\therefore$ n = 2

$\Delta$G$^\circ$ = $-$2 $\times$ 96487 $\times$ 1.1

$\Delta$G$^\circ$ = $-$212271.4 J mol$-$1

$\Delta$G$^\circ$ = $-$212.27 kJ mol$-$1

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