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Electrochemistry question

2022 · Q107
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Electrochemistry question

2022 · Q107

NEETChemistryElectrochemistryMCQ+4 / −1

At 298 K, the standard electrode potentials of Cu2+ / Cu, Zn2+ / Zn, Fe2+ / Fe and Ag+ / Ag are 0.34 V, −-−0.76 V, −-−0.44 V V and 0.80 V, respectively.

On the basis of standard electrode potential, predict which of the following reaction cannot occur?

  1. A
    CuSO4(aq) + Zn(s) →\to→ ZnSO4(aq) + Cu(s)
  2. B
    CuSO4(aq) + Fe(s) →\to→ FeSO4(aq) + Cu(s)
  3. C
    FeSO4(aq) + Zn(s) →\to→ ZnSO4(aq) + Fe(s)
  4. D
    2CuSO4(aq) + 2Ag(s) →\to→ 2Cu(s) + Ag2SO4(aq)
View written solutionFree

Correct answer: D

For a reaction to be spontaneous, E$_{cell}^o$ must be positive.

$\bullet$ For, FeSO4(aq) + Zn(s) $\to$ ZnSO4(aq) + Fe(s)

E$_{cell}^o$ = E$_{cathode}^o$ $-$ E$_{anode}^o$

= $-$0.44 V $-$ ($-$0.76 V)

= 0.32 V

$\bullet$ For, 2CuSO4(aq) + 2Ag(s) $\to$ 2Cu(s) + Ag2SO4(aq)

E$_{cell}^o$ = 0.34 V $-$ 0.80 V

= $-$0.46 V

$\bullet$ For, CuSO4(aq) + Zn(s) $\to$ ZnSO4(aq) + Cu(s)

E$_{cell}^o$ = 0.34 V $-$ ($-$0.76 V)

= 1.1 V

$\bullet$ For, CuSO4(aq) + Fe(s) $\to$ FeSO4(aq) + Cu(s)

E$_{cell}^o$ = 0.80 V $-$ ($-$0.44 V)

= 1.24 V

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