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Electrochemistry question

2016 · Q89
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Electrochemistry question

2016 · Q89

NEETChemistryElectrochemistryMCQ+4 / −1
The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76 ×\times× 10−-−3 S cm−-−1 at 298 K is
  1. A
    2.88 S cm2/mol
  2. B
    11.52 S cm2/mol
  3. C
    0.086 S cm2/mol
  4. D
    28.8 S cm2/mol
View written solutionFree

Correct answer: B

Λm=κ×1000Molality{\Lambda _m} = {{\kappa \times 1000} \over {Molality}}Λm​=Molalityκ×1000​

= 5.76×10−3×10000.5{{5.76 \times {{10}^{ - 3}} \times 1000} \over {0.5}}0.55.76×10−3×1000​

= 11.52 S cm2/mol

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