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Coordination Compounds question

2024 · Q132
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Coordination Compounds question

2024 · Q132

NEETChemistryCoordination CompoundsMCQ+4 / −1

Given below are two statements :

Statement I: Both [Co(NH3)6]3+[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}[Co(NH3​)6​]3+ and [CoF6]3−[\mathrm{CoF}_6]^{3-}[CoF6​]3− complexes are octahedral but differ in their magnetic behaviour.

Statement II: [Co(NH3)6]3+[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}[Co(NH3​)6​]3+ is diamagnetic whereas [CoF6]3−[\mathrm{CoF}_6]^{3-}[CoF6​]3− is paramagnetic.

In the light of the above statements, choose the correct answer from the options given below:

  1. A
    Both Statement I and Statement II are true
  2. B
    Both Statement I and Statement II are false
  3. C
    Statement I is true but Statement II is false
  4. D
    Statement I is false but Statement II is true
View written solutionFree

Correct answer: A

$$ \text { In }\left[\mathrm{Co}\left(\mathrm{NH}_3\right) 6\right]^{3+}, \mathrm{Co}^{3+} \text { ion is having } 3 \mathrm{~d}^6 \text { configuration. } $$

NEET 2024 Chemistry - Coordination Compounds Question 7 English Explanation 1

$$ \text { In presence of } \mathrm{NH}_3 \text { ligand, pairing of electrons takes place and it becomes diamagnetic complex ion. } $$

NEET 2024 Chemistry - Coordination Compounds Question 7 English Explanation 2

$$\therefore \quad\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$$ is octahedral with $$\mathrm{d}^2 \mathrm{sp}^3$$ hybridisation and it is diamagnetic in nature. In case of [CoF6]3-, Co is in +3 oxidation state and it is having 3d6 configuration.

In presence of weak field $\mathrm{F}$ - ligand, pairing does not take place.

NEET 2024 Chemistry - Coordination Compounds Question 7 English Explanation 3

$$ \therefore \quad \ln \left[\mathrm{CoF}_6\right]^{3-}, \mathrm{Co}^{3+} \text { is } \mathrm{sp}^3 \mathrm{~d}^2 \text { hybridised with four unpaired electrons, so it is paramagnetic in nature. } $$

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