NEETChemistryCoordination CompoundsMCQ+4 / −1
An excess of AgNO3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be
- A0.003
- B0.01
- C0.001
- D0.002
View written solutionFree
Correct answer: C
AgNO3 + [Cr(H2O)4Cl2]Cl AgCl
Excess mole = MV
= 0.01
= 0.001
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