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Coordination Compounds question

2011 · Q102
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Coordination Compounds question

2011 · Q102

NEETChemistryCoordination CompoundsMCQ+4 / −1
The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d4, d5, d6 and d7 respectively. Which one of the following will exhibit minimum paramagnetic behaviour?
(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)
  1. A
    [Mn(H2O)6]2+
  2. B
    [Fe(H2O)6]2+
  3. C
    [Co(H2O)6]2+
  4. D
    [Cr(H2O)6]2+
View written solutionFree

Correct answer: C

[Mn(H2O)6]2+ : Mn2+ = 3d5

∴\therefore∴ Number of unpaired electron = 5

[Fe(H2O)6]2+ : Fe2+ = 3d6

∴\therefore∴ Number of unpaired electrons = 4

[Co(H2O)6]2+ : Co2+ = 3d7

∴\therefore∴ Number of unpaired electrons = 3

[Cr(H2O)6]2+ : Cr2+ = 3d4

Number of unpaired electrons = 4

Minimum paramagnetic behaviour is shown by [Co(H2O)6]2+.

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