NEETChemistryCoordination CompoundsMCQ+4 / −1
A magnetic moment at 1.73 BM will be shown by one among of the following
- ATiCl4
- B[CoCl6]4
- C[Cu(NH3)4]2+
- D[Ni(CN)4]2
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Correct answer: C
For = 1.73 B.M. n will be :
1.73 =
n = 1
In [Cu(NH3)4]2+. Cu+2 = [Ar]3d9

NH3 = Strong field ligand
Here, unpaired electron gets excited to higher energy level but it still remains unpaired.
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