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Chemical Kinetics question

2004 · Q81
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Chemical Kinetics question

2004 · Q81

NEETChemistryChemical KineticsMCQ+4 / −1
The rate of a first order reaction is 1.5 ×\times× 10−-−2 mol L−-−1 min−-−1 at 0.5 M concentration of the reactant. The half-life of the reaction is
  1. A
    0.383 min
  2. B
    23.1 min
  3. C
    8.73 min
  4. D
    7.53 min
View written solutionFree

Correct answer: B

For a first order reaction, A →\to→ products

Rate(r) = k[A]

⇒\Rightarrow⇒ k = r[A]{r \over {\left[ A \right]}}[A]r​

⇒\Rightarrow⇒ k = 1.5×10−20.5=3×10−2{{1.5 \times {{10}^{ - 2}}} \over {0.5}} = 3 \times {10^{ - 2}}0.51.5×10−2​=3×10−2

So, t1/2=0.6933×10−2{t_{1/2}} = {{0.693} \over {3 \times {{10}^{ - 2}}}}t1/2​=3×10−20.693​ = 23.1 min

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