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Chemical Equilibrium question

2014 · Q110
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Chemical Equilibrium question

2014 · Q110

NEETChemistryChemical EquilibriumMCQ+4 / −1
Using the Gibb's energy change, Δ\DeltaΔGo = +63.3 kJ, for the following reaction,

Ag2CO3(s) ⇌\rightleftharpoons⇌ 2 Ag+(aq) + CO32−-− (aq)
the Ksp of Ag2CO3(s) in water at 25oC is
(R = 8.314 J K−-−1 mol−-−1)
  1. A
    3.2 ×\times× 10−-−26
  2. B
    8.0 ×\times× 10−-−12
  3. C
    2.9 ×\times× 10−-−3
  4. D
    7.9 ×\times× 10−-−2
View written solutionFree

Correct answer: B

We know, Δ\Delta ΔGo = – 2.303 RT log Ksp

∴\therefore∴ 63300 = – 2.303 × 8.314 × 298 log Ksp

⇒\Rightarrow⇒ log Ksp = -11.09

⇒\Rightarrow⇒ Ksp = 10-11.09

= 8.0 × 10–12

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