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Chemical Equilibrium question

2011 · Q117
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Chemical Equilibrium question

2011 · Q117

NEETChemistryChemical EquilibriumMCQ+4 / −1
For the reaction, N2(g) + O2(g) ⇌\rightleftharpoons⇌ 2NO(g), the equilibrium constant is K1. The equilibrium constant is K2 for the reaction,
2NO(g) + O2(g) ⇌\rightleftharpoons⇌ 2NO2(g)
What is K for the reaction,
NO2(g) ⇌\rightleftharpoons⇌ 12{1 \over 2}21​N2(g) + O2(g)
  1. A
    12K1K2{1 \over {2{K_1}{K_2}}}2K1​K2​1​
  2. B
    14K1K2{1 \over {4{K_1}{K_2}}}4K1​K2​1​
  3. C
    [1K1K2]1/2{\left[ {{1 \over {{K_1}{K_2}}}} \right]^{1/2}}[K1​K2​1​]1/2
  4. D
    1K1K2{1 \over {{K_1}{K_2}}}K1​K2​1​
View written solutionFree

Correct answer: C

N2(g) + 12{1 \over 2}21​O2(g) ⇌\rightleftharpoons⇌ NO(g),     (K1)12{\left( {{K_1}} \right)^{{1 \over 2}}}(K1​)21​

NO(g) + 12{1 \over 2}21​O2(g) ⇌\rightleftharpoons⇌ NO2(g),     (K2)12{\left( {{K_2}} \right)^{{1 \over 2}}}(K2​)21​
---------------------------------------------------
12{1 \over 2}21​N2(g) + O2(g) ⇌\rightleftharpoons⇌ NO2(g)    (K1K2)12{\left( {{K_1}{K_2}} \right)^{{1 \over 2}}}(K1​K2​)21​

So, for the reverse reaction which is the desired one the value of K will be reciprocal of this value. i.e.

K = [1K1K2]1/2{\left[ {{1 \over {{K_1}{K_2}}}} \right]^{1/2}}[K1​K2​1​]1/2

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