Match List I with List II. .tg border-collapse:collapse;border-spacing:0; .tg tdborder-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal; .tg thborder-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal; .tg .tg-c3owborder-color:inherit;text-align:center;vertical-align:top .tg .tg-7bttborder-color:inherit;font-weight:bold;text-align:center;vertical-align:top .tg .tg-0pkyborder-color:inherit;text-align:left;vertical-align:top List I (Compound) List II (Shape/geometry) A. NH _3 I. Trigonal Pyramidal B. BrF _5 II. Square Planar C. XeF _4 III. Octahedral D. SF _6 IV. Square Pyramidal Choose the correct answer from the options given below:

Chemical Bonding and Molecular Structure PYQ — NEET 2024 · Q116 with Solution

Match List I with List II.

Choose the correct answer from the options given below:

View written solutionFree

Correct answer: A

$$\mathrm{NH}_3 \Rightarrow s p^3$$ hybridised with 1 lone pair.

Structure will be Trigonal Pyramidal.

$$\mathrm{BrF}_5 \Rightarrow s p^3 d^2$$ hybridised with 1 lone pair.

Structure will be Square Pyramidal.

$$\mathrm{XeF}_4 \Rightarrow s p^3 d^2$$ with two lone pairs.

Structure will be Square Planar.

$$\mathrm{SF}_6 \Rightarrow s p^3 d^2$$ with no lone pair.

Structure will be Octahedral.

A-I, B-IV, C-II, D-III