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Work Power and Energy question

2025 · 24 Jan · Shift 1 · Q61
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Work Power and Energy question

2025 · 24 Jan · Shift 1 · Q61

JEE MainPhysicsWork Power and EnergyMCQ+4 / −1
A force F=α+βx2\mathrm{F}=\alpha+\beta \mathrm{x}^2F=α+βx2 acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m . If the constant α=1 N\alpha=1 \mathrm{~N}α=1 N then β\betaβ will be
  1. A
    15 N/m215 \mathrm{~N} / \mathrm{m}^215 N/m2
  2. B
    10 N/m210 \mathrm{~N} / \mathrm{m}^210 N/m2
  3. C
    12 N/m212 \mathrm{~N} / \mathrm{m}^212 N/m2
  4. D
    8 N/m28 \mathrm{~N} / \mathrm{m}^28 N/m2
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