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Work Power and Energy question

2023 · 1 Feb · Shift 2 · Q71
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Work Power and Energy question

2023 · 1 Feb · Shift 2 · Q71

JEE MainPhysicsWork Power and EnergyNumerical+4 / −1
A force F=(5+3y2)\mathrm{F}=\left(5+3 y^{2}\right)F=(5+3y2) acts on a particle in the yyy-direction, where F\mathrm{F}F is in newton and yyy is in meter. The work done by the force during a displacement from y=2 my=2 \mathrm{~m}y=2 m to y=5 my=5 \mathrm{~m}y=5 m is ‾\underline{\hspace{2cm}}​ J.
Numerical answer
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