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Work Power and Energy question

2023 · 10 Apr · Shift 2 · Q61

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Work Power and Energy
2023 · 10 Apr · Shift 2 · Q61

Work Power and Energy question

2023 · 10 Apr · Shift 2 · Q61

JEE MainPhysicsWork Power and EnergyNumerical+4 / −1

If the maximum load carried by an elevator is

1400 \mathrm{~kg}

(

600 \mathrm{~kg}

- Passengers + 800

\mathrm{kg}

- elevator), which is moving up with a uniform speed of

3 \mathrm{~m} \mathrm{~s}^{-1}

and the frictional force acting on it is

2000 \mathrm{~N}

, then the maximum power used by the motor is

\underline{\hspace{2cm}}

\mathrm{kW}\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)

Numerical answer

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