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Waves question

2008 · Shift 0 · Q75
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Waves question

2008 · Shift 0 · Q75

JEE MainPhysicsWavesMCQ+4 / −1
While measuring the speed of sound by performing a resonance column experiment, a student gets the first resonance condition at a column length of 18cm18cm18cm during winter. Repeating the same experiment during summer, she measures the column length to be xcmxcmxcm for the second resonance. Then
  1. A
    18>x18 \gt x18>x
  2. B
    x>54x \gt 54x>54
  3. C
    54>x>3654 \gt x \gt 3654>x>36
  4. D
    36>x>1836 \gt x \gt 1836>x>18
View written solutionFree

Correct answer: B

  1. Resonance column relation

For a resonance column experiment with one end closed, resonance occurs at

Ln=(2n−1)λ4,n=1,2,3,…L_n=(2n-1)\frac{\lambda}{4}, \quad n=1,2,3,\dotsLn​=(2n−1)4λ​,n=1,2,3,…

So:

  • First resonance: L1=λ4L_1=\frac{\lambda}{4}L1​=4λ​
  • Second resonance: L2=3λ4L_2=\frac{3\lambda}{4}L2​=43λ​
  1. Winter observation

The first resonance length in winter is given as

L1=18 cmL_1=18\text{ cm}L1​=18 cm

Hence winter wavelength is

λw=4×18=72 cm\lambda_w=4\times 18=72\text{ cm}λw​=4×18=72 cm

  1. Effect of summer

Speed of sound in air increases in summer because temperature is higher.

Using

v=fλv=f\lambdav=fλ

and noting that the tuning fork frequency fff remains constant, a larger speed means a larger wavelength in summer:

λs>λw=72 cm\lambda_s>\lambda_w=72\text{ cm}λs​>λw​=72 cm

  1. Second resonance in summer

For second resonance in summer,

x=L2=3λs4x=L_2=\frac{3\lambda_s}{4}x=L2​=43λs​​

Since λs>72\lambda_s>72λs​>72 cm,

x>3×724=54 cmx>\frac{3\times 72}{4}=54\text{ cm}x>43×72​=54 cm

Thus,

x>54x>54x>54

  1. Checking options
  • A: 18>x18>x18>x → false
  • B: x>54x>54x>54 → true
  • C: 54>x>3654>x>3654>x>36 → false
  • D: 36>x>1836>x>1836>x>18 → false

Therefore, the correct option is B.

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