JEE MainPhysicsWavesMCQ+4 / −1
A string is stretched between fixed points separated by It is observed to have resonant frequencies of and . There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is
- A
- B
- C
- D
View written solutionFree
Correct answer: A
- Resonant frequencies of a string fixed at both ends
For a string fixed at both ends, allowed resonant frequencies are:
where:
- is the fundamental (lowest resonant frequency).
So all resonant frequencies are equally spaced by .
- Use the given frequencies
Two resonant frequencies are given:
And it is stated that there are no other resonant frequencies between them.
This means these two frequencies must be consecutive harmonics.
Hence their difference equals the fundamental frequency:
- Check
If , then:
So these are indeed consecutive harmonics ( and ), with no resonance in between.
- Final answer
The lowest resonant frequency is:
So the correct option is A.
- Comparison with stored answer
Stored correct answer: A
My derived answer: A
They agree.
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